7(3x-2)-2(4x-10)=3(4x+5)-14

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Solution for 7(3x-2)-2(4x-10)=3(4x+5)-14 equation: 



7(3x-2)-2(4x-10)=3(4x+5)-14

We move all terms to the left:

7(3x-2)-2(4x-10)-(3(4x+5)-14)=0

We multiply parentheses

21x-8x-(3(4x+5)-14)-14+20=0



We calculate terms in parentheses: -(3(4x+5)-14), so:

3(4x+5)-14

We multiply parentheses

12x+15-14

We add all the numbers together, and all the variables

12x+1

Back to the equation:

-(12x+1)



We add all the numbers together, and all the variables

13x-(12x+1)+6=0

We get rid of parentheses

13x-12x-1+6=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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