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7(3x-10)-2(x-3)=4(2x+3)
We move all terms to the left:
7(3x-10)-2(x-3)-(4(2x+3))=0
We multiply parentheses
21x-2x-(4(2x+3))-70+6=0
We calculate terms in parentheses: -(4(2x+3)), so:We add all the numbers together, and all the variables
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
19x-(8x+12)-64=0
We get rid of parentheses
19x-8x-12-64=0
We add all the numbers together, and all the variables
11x-76=0
We move all terms containing x to the left, all other terms to the right
11x=76
x=76/11
x=6+10/11
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