7(3x+4)=11(x-1)+19

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Solution for 7(3x+4)=11(x-1)+19 equation: 



7(3x+4)=11(x-1)+19

We move all terms to the left:

7(3x+4)-(11(x-1)+19)=0

We multiply parentheses

21x-(11(x-1)+19)+28=0



We calculate terms in parentheses: -(11(x-1)+19), so:

11(x-1)+19

We multiply parentheses

11x-11+19

We add all the numbers together, and all the variables

11x+8

Back to the equation:

-(11x+8)



We get rid of parentheses

21x-11x-8+28=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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