7(3x+2)=8(2x-2)

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Solution for 7(3x+2)=8(2x-2) equation: 



7(3x+2)=8(2x-2)

We move all terms to the left:

7(3x+2)-(8(2x-2))=0

We multiply parentheses

21x-(8(2x-2))+14=0



We calculate terms in parentheses: -(8(2x-2)), so:

8(2x-2)

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We get rid of parentheses

21x-16x+16+14=0

We add all the numbers together, and all the variables

5x+30=0

We move all terms containing x to the left, all other terms to the right

5x=-30

x=-30/5

x=-6

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