7(3x+2)-(4x-3)=4(x-2)=4(x-2)+1

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Solution for 7(3x+2)-(4x-3)=4(x-2)=4(x-2)+1 equation: 



7(3x+2)-(4x-3)=4(x-2)=4(x-2)+1

We move all terms to the left:

7(3x+2)-(4x-3)-(4(x-2))=0

We multiply parentheses

21x-(4x-3)-(4(x-2))+14=0

We get rid of parentheses

21x-4x-(4(x-2))+3+14=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

17x-(4x-8)+17=0

We get rid of parentheses

17x-4x+8+17=0

We add all the numbers together, and all the variables

13x+25=0

We move all terms containing x to the left, all other terms to the right

13x=-25

x=-25/13

x=-1+12/13

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