7(3x+1)=-3(7x-2)

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Solution for 7(3x+1)=-3(7x-2) equation: 



7(3x+1)=-3(7x-2)

We move all terms to the left:

7(3x+1)-(-3(7x-2))=0

We multiply parentheses

21x-(-3(7x-2))+7=0



We calculate terms in parentheses: -(-3(7x-2)), so:

-3(7x-2)

We multiply parentheses

-21x+6

Back to the equation:

-(-21x+6)



We get rid of parentheses

21x+21x-6+7=0

We add all the numbers together, and all the variables

42x+1=0

We move all terms containing x to the left, all other terms to the right

42x=-1

x=-1/42

x=-1/42

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