7(3x+1)+1=4(2x+1)+43

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Solution for 7(3x+1)+1=4(2x+1)+43 equation:


Simplifying
7(3x + 1) + 1 = 4(2x + 1) + 43

Reorder the terms:
7(1 + 3x) + 1 = 4(2x + 1) + 43
(1 * 7 + 3x * 7) + 1 = 4(2x + 1) + 43
(7 + 21x) + 1 = 4(2x + 1) + 43

Reorder the terms:
7 + 1 + 21x = 4(2x + 1) + 43

Combine like terms: 7 + 1 = 8
8 + 21x = 4(2x + 1) + 43

Reorder the terms:
8 + 21x = 4(1 + 2x) + 43
8 + 21x = (1 * 4 + 2x * 4) + 43
8 + 21x = (4 + 8x) + 43

Reorder the terms:
8 + 21x = 4 + 43 + 8x

Combine like terms: 4 + 43 = 47
8 + 21x = 47 + 8x

Solving
8 + 21x = 47 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
8 + 21x + -8x = 47 + 8x + -8x

Combine like terms: 21x + -8x = 13x
8 + 13x = 47 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 + 13x = 47 + 0
8 + 13x = 47

Add '-8' to each side of the equation.
8 + -8 + 13x = 47 + -8

Combine like terms: 8 + -8 = 0
0 + 13x = 47 + -8
13x = 47 + -8

Combine like terms: 47 + -8 = 39
13x = 39

Divide each side by '13'.
x = 3

Simplifying
x = 3

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