7(3r+2)=5(r-4)

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Solution for 7(3r+2)=5(r-4) equation: 



7(3r+2)=5(r-4)

We move all terms to the left:

7(3r+2)-(5(r-4))=0

We multiply parentheses

21r-(5(r-4))+14=0



We calculate terms in parentheses: -(5(r-4)), so:

5(r-4)

We multiply parentheses

5r-20

Back to the equation:

-(5r-20)



We get rid of parentheses

21r-5r+20+14=0

We add all the numbers together, and all the variables

16r+34=0

We move all terms containing r to the left, all other terms to the right

16r=-34

r=-34/16

r=-2+1/8

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