7(3n-4)=(7n+3)+7

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Solution for 7(3n-4)=(7n+3)+7 equation: 



7(3n-4)=(7n+3)+7

We move all terms to the left:

7(3n-4)-((7n+3)+7)=0

We multiply parentheses

21n-((7n+3)+7)-28=0



We calculate terms in parentheses: -((7n+3)+7), so:

(7n+3)+7

We get rid of parentheses

7n+3+7

We add all the numbers together, and all the variables

7n+10

Back to the equation:

-(7n+10)



We get rid of parentheses

21n-7n-10-28=0

We add all the numbers together, and all the variables

14n-38=0

We move all terms containing n to the left, all other terms to the right

14n=38

n=38/14

n=2+5/7

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