7(3n+4)=6(7n+3)+1

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Solution for 7(3n+4)=6(7n+3)+1 equation: 



7(3n+4)=6(7n+3)+1

We move all terms to the left:

7(3n+4)-(6(7n+3)+1)=0

We multiply parentheses

21n-(6(7n+3)+1)+28=0



We calculate terms in parentheses: -(6(7n+3)+1), so:

6(7n+3)+1

We multiply parentheses

42n+18+1

We add all the numbers together, and all the variables

42n+19

Back to the equation:

-(42n+19)



We get rid of parentheses

21n-42n-19+28=0

We add all the numbers together, and all the variables

-21n+9=0

We move all terms containing n to the left, all other terms to the right

-21n=-9

n=-9/-21

n=3/7

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