7(3n+1)=6(7n+5)+9

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Solution for 7(3n+1)=6(7n+5)+9 equation: 



7(3n+1)=6(7n+5)+9

We move all terms to the left:

7(3n+1)-(6(7n+5)+9)=0

We multiply parentheses

21n-(6(7n+5)+9)+7=0



We calculate terms in parentheses: -(6(7n+5)+9), so:

6(7n+5)+9

We multiply parentheses

42n+30+9

We add all the numbers together, and all the variables

42n+39

Back to the equation:

-(42n+39)



We get rid of parentheses

21n-42n-39+7=0

We add all the numbers together, and all the variables

-21n-32=0

We move all terms containing n to the left, all other terms to the right

-21n=32

n=32/-21

n=-1+11/21

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