7(3m+2)-6=2(5m-3)+4

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Solution for 7(3m+2)-6=2(5m-3)+4 equation: 



7(3m+2)-6=2(5m-3)+4

We move all terms to the left:

7(3m+2)-6-(2(5m-3)+4)=0

We multiply parentheses

21m-(2(5m-3)+4)+14-6=0



We calculate terms in parentheses: -(2(5m-3)+4), so:

2(5m-3)+4

We multiply parentheses

10m-6+4

We add all the numbers together, and all the variables

10m-2

Back to the equation:

-(10m-2)



We add all the numbers together, and all the variables

21m-(10m-2)+8=0

We get rid of parentheses

21m-10m+2+8=0

We add all the numbers together, and all the variables

11m+10=0

We move all terms containing m to the left, all other terms to the right

11m=-10

m=-10/11

m=-10/11

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