7(3j-8)=2(6j+8)

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Solution for 7(3j-8)=2(6j+8) equation: 



7(3j-8)=2(6j+8)

We move all terms to the left:

7(3j-8)-(2(6j+8))=0

We multiply parentheses

21j-(2(6j+8))-56=0



We calculate terms in parentheses: -(2(6j+8)), so:

2(6j+8)

We multiply parentheses

12j+16

Back to the equation:

-(12j+16)



We get rid of parentheses

21j-12j-16-56=0

We add all the numbers together, and all the variables

9j-72=0

We move all terms containing j to the left, all other terms to the right

9j=72

j=72/9

j=8

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