7(3b-7)=7(5b-1)

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Solution for 7(3b-7)=7(5b-1) equation: 



7(3b-7)=7(5b-1)

We move all terms to the left:

7(3b-7)-(7(5b-1))=0

We multiply parentheses

21b-(7(5b-1))-49=0



We calculate terms in parentheses: -(7(5b-1)), so:

7(5b-1)

We multiply parentheses

35b-7

Back to the equation:

-(35b-7)



We get rid of parentheses

21b-35b+7-49=0

We add all the numbers together, and all the variables

-14b-42=0

We move all terms containing b to the left, all other terms to the right

-14b=42

b=42/-14

b=-3

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