7(3b+1)+(22b-5)=0

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Solution for 7(3b+1)+(22b-5)=0 equation:


Simplifying
7(3b + 1) + (22b + -5) = 0

Reorder the terms:
7(1 + 3b) + (22b + -5) = 0
(1 * 7 + 3b * 7) + (22b + -5) = 0
(7 + 21b) + (22b + -5) = 0

Reorder the terms:
7 + 21b + (-5 + 22b) = 0

Remove parenthesis around (-5 + 22b)
7 + 21b + -5 + 22b = 0

Reorder the terms:
7 + -5 + 21b + 22b = 0

Combine like terms: 7 + -5 = 2
2 + 21b + 22b = 0

Combine like terms: 21b + 22b = 43b
2 + 43b = 0

Solving
2 + 43b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 43b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 43b = 0 + -2
43b = 0 + -2

Combine like terms: 0 + -2 = -2
43b = -2

Divide each side by '43'.
b = -0.04651162791

Simplifying
b = -0.04651162791

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