7(3a+4)=11(a-)+19

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Solution for 7(3a+4)=11(a-)+19 equation: 



7(3a+4)=11(a-)+19

We move all terms to the left:

7(3a+4)-(11(a-)+19)=0

We add all the numbers together, and all the variables

7(3a+4)-(11(+a)+19)=0

We multiply parentheses

21a-(11(+a)+19)+28=0



We calculate terms in parentheses: -(11(+a)+19), so:

11(+a)+19

We multiply parentheses

11a+19

Back to the equation:

-(11a+19)



We get rid of parentheses

21a-11a-19+28=0

We add all the numbers together, and all the variables

10a+9=0

We move all terms containing a to the left, all other terms to the right

10a=-9

a=-9/10

a=-9/10

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