7(3-2x)+3(5+4x)=26

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Solution for 7(3-2x)+3(5+4x)=26 equation: 



7(3-2x)+3(5+4x)=26

We move all terms to the left:

7(3-2x)+3(5+4x)-(26)=0

We add all the numbers together, and all the variables

7(-2x+3)+3(4x+5)-26=0

We multiply parentheses

-14x+12x+21+15-26=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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