7(2y+1)=35

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Solution for 7(2y+1)=35 equation: 



7(2y+1)=35

We move all terms to the left:

7(2y+1)-(35)=0

We multiply parentheses

14y+7-35=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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