7(2x-5a)/3b=21(4a-2)

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Solution for 7(2x-5a)/3b=21(4a-2) equation:


x in (-oo:+oo)

b*((7*(2*x-(5*a)))/3) = 21*(4*a-2) // - 21*(4*a-2)

b*((7*(2*x-(5*a)))/3)-(21*(4*a-2)) = 0

b*((7*(2*x-5*a))/3)-21*(4*a-2) = 0

(7*b*(2*x-5*a))/3-21*(4*a-2) = 0

(7*b*(2*x-5*a))/3+(-21*3*(4*a-2))/3 = 0

7*b*(2*x-5*a)-21*3*(4*a-2) = 0

14*b*x-252*a-35*a*b+126 = 0

(14*b*x-252*a-35*a*b+126)/3 = 0

(14*b*x-252*a-35*a*b+126)/3 = 0 // * 3

14*b*x-252*a-35*a*b+126 = 0

14*b*x-252*a-35*a*b+126 = 0 // - 126-252*a-35*a*b

14*b*x = -(126-252*a-35*a*b) // : 14*b

x = (-(126-252*a-35*a*b))/(14*b)

x = (-1/14)*b^-1*(126-252*a-35*a*b)

x = (-1/14)*b^-1*(126-252*a-35*a*b)

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