7(2x-5)=3(x-5)+13

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Solution for 7(2x-5)=3(x-5)+13 equation: 



7(2x-5)=3(x-5)+13

We move all terms to the left:

7(2x-5)-(3(x-5)+13)=0

We multiply parentheses

14x-(3(x-5)+13)-35=0



We calculate terms in parentheses: -(3(x-5)+13), so:

3(x-5)+13

We multiply parentheses

3x-15+13

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

14x-3x+2-35=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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