7(2x-3)+6=-2(6x-20)1

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Solution for 7(2x-3)+6=-2(6x-20)1 equation: 



7(2x-3)+6=-2(6x-20)1

We move all terms to the left:

7(2x-3)+6-(-2(6x-20)1)=0

We multiply parentheses

14x-(-2(6x-20)1)-21+6=0



We calculate terms in parentheses: -(-2(6x-20)1), so:

-2(6x-20)1

We multiply parentheses

-12x+40

Back to the equation:

-(-12x+40)



We add all the numbers together, and all the variables

14x-(-12x+40)-15=0

We get rid of parentheses

14x+12x-40-15=0

We add all the numbers together, and all the variables

26x-55=0

We move all terms containing x to the left, all other terms to the right

26x=55

x=55/26

x=2+3/26

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