7(2x-3)+18=62+2x

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Solution for 7(2x-3)+18=62+2x equation: 



7(2x-3)+18=62+2x

We move all terms to the left:

7(2x-3)+18-(62+2x)=0

We add all the numbers together, and all the variables

7(2x-3)-(2x+62)+18=0

We multiply parentheses

14x-(2x+62)-21+18=0

We get rid of parentheses

14x-2x-62-21+18=0

We add all the numbers together, and all the variables

12x-65=0

We move all terms containing x to the left, all other terms to the right

12x=65

x=65/12

x=5+5/12

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