7(2x-10)+6x=10+4(5x-20)

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Solution for 7(2x-10)+6x=10+4(5x-20) equation:



7(2x-10)+6x=10+4(5x-20)
We move all terms to the left:
7(2x-10)+6x-(10+4(5x-20))=0
We add all the numbers together, and all the variables
6x+7(2x-10)-(10+4(5x-20))=0
We multiply parentheses
6x+14x-(10+4(5x-20))-70=0
We calculate terms in parentheses: -(10+4(5x-20)), so:
10+4(5x-20)
determiningTheFunctionDomain 4(5x-20)+10
We multiply parentheses
20x-80+10
We add all the numbers together, and all the variables
20x-70
Back to the equation:
-(20x-70)
We add all the numbers together, and all the variables
20x-(20x-70)-70=0
We get rid of parentheses
20x-20x+70-70=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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