7(2x+4)+6=6(x+2)-10

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Solution for 7(2x+4)+6=6(x+2)-10 equation: 



7(2x+4)+6=6(x+2)-10

We move all terms to the left:

7(2x+4)+6-(6(x+2)-10)=0

We multiply parentheses

14x-(6(x+2)-10)+28+6=0



We calculate terms in parentheses: -(6(x+2)-10), so:

6(x+2)-10

We multiply parentheses

6x+12-10

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

14x-(6x+2)+34=0

We get rid of parentheses

14x-6x-2+34=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4

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