7(2x+4)+15=3(2x+7)+50

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Solution for 7(2x+4)+15=3(2x+7)+50 equation: 



7(2x+4)+15=3(2x+7)+50

We move all terms to the left:

7(2x+4)+15-(3(2x+7)+50)=0

We multiply parentheses

14x-(3(2x+7)+50)+28+15=0



We calculate terms in parentheses: -(3(2x+7)+50), so:

3(2x+7)+50

We multiply parentheses

6x+21+50

We add all the numbers together, and all the variables

6x+71

Back to the equation:

-(6x+71)



We add all the numbers together, and all the variables

14x-(6x+71)+43=0

We get rid of parentheses

14x-6x-71+43=0

We add all the numbers together, and all the variables

8x-28=0

We move all terms containing x to the left, all other terms to the right

8x=28

x=28/8

x=3+1/2

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