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7(2x+3)=(6+x)
We move all terms to the left:
7(2x+3)-((6+x))=0
We add all the numbers together, and all the variables
7(2x+3)-((x+6))=0
We multiply parentheses
14x-((x+6))+21=0
We calculate terms in parentheses: -((x+6)), so:We get rid of parentheses
(x+6)
We get rid of parentheses
x+6
Back to the equation:
-(x+6)
14x-x-6+21=0
We add all the numbers together, and all the variables
13x+15=0
We move all terms containing x to the left, all other terms to the right
13x=-15
x=-15/13
x=-1+2/13
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