7(2x+1)=2(x+33)

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Solution for 7(2x+1)=2(x+33) equation: 



7(2x+1)=2(x+33)

We move all terms to the left:

7(2x+1)-(2(x+33))=0

We multiply parentheses

14x-(2(x+33))+7=0



We calculate terms in parentheses: -(2(x+33)), so:

2(x+33)

We multiply parentheses

2x+66

Back to the equation:

-(2x+66)



We get rid of parentheses

14x-2x-66+7=0

We add all the numbers together, and all the variables

12x-59=0

We move all terms containing x to the left, all other terms to the right

12x=59

x=59/12

x=4+11/12

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