7(2x+1)-3=14(x-1)+10

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Solution for 7(2x+1)-3=14(x-1)+10 equation:


Simplifying
7(2x + 1) + -3 = 14(x + -1) + 10

Reorder the terms:
7(1 + 2x) + -3 = 14(x + -1) + 10
(1 * 7 + 2x * 7) + -3 = 14(x + -1) + 10
(7 + 14x) + -3 = 14(x + -1) + 10

Reorder the terms:
7 + -3 + 14x = 14(x + -1) + 10

Combine like terms: 7 + -3 = 4
4 + 14x = 14(x + -1) + 10

Reorder the terms:
4 + 14x = 14(-1 + x) + 10
4 + 14x = (-1 * 14 + x * 14) + 10
4 + 14x = (-14 + 14x) + 10

Reorder the terms:
4 + 14x = -14 + 10 + 14x

Combine like terms: -14 + 10 = -4
4 + 14x = -4 + 14x

Add '-14x' to each side of the equation.
4 + 14x + -14x = -4 + 14x + -14x

Combine like terms: 14x + -14x = 0
4 + 0 = -4 + 14x + -14x
4 = -4 + 14x + -14x

Combine like terms: 14x + -14x = 0
4 = -4 + 0
4 = -4

Solving
4 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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