7(2x+1)-2=14(x-2)+33

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Solution for 7(2x+1)-2=14(x-2)+33 equation:


Simplifying
7(2x + 1) + -2 = 14(x + -2) + 33

Reorder the terms:
7(1 + 2x) + -2 = 14(x + -2) + 33
(1 * 7 + 2x * 7) + -2 = 14(x + -2) + 33
(7 + 14x) + -2 = 14(x + -2) + 33

Reorder the terms:
7 + -2 + 14x = 14(x + -2) + 33

Combine like terms: 7 + -2 = 5
5 + 14x = 14(x + -2) + 33

Reorder the terms:
5 + 14x = 14(-2 + x) + 33
5 + 14x = (-2 * 14 + x * 14) + 33
5 + 14x = (-28 + 14x) + 33

Reorder the terms:
5 + 14x = -28 + 33 + 14x

Combine like terms: -28 + 33 = 5
5 + 14x = 5 + 14x

Add '-5' to each side of the equation.
5 + -5 + 14x = 5 + -5 + 14x

Combine like terms: 5 + -5 = 0
0 + 14x = 5 + -5 + 14x
14x = 5 + -5 + 14x

Combine like terms: 5 + -5 = 0
14x = 0 + 14x
14x = 14x

Add '-14x' to each side of the equation.
14x + -14x = 14x + -14x

Combine like terms: 14x + -14x = 0
0 = 14x + -14x

Combine like terms: 14x + -14x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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