7(2p+1)=7p+35

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Solution for 7(2p+1)=7p+35 equation: 



7(2p+1)=7p+35

We move all terms to the left:

7(2p+1)-(7p+35)=0

We multiply parentheses

14p-(7p+35)+7=0

We get rid of parentheses

14p-7p-35+7=0

We add all the numbers together, and all the variables

7p-28=0

We move all terms containing p to the left, all other terms to the right

7p=28

p=28/7

p=4

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