7(2p+1)=2(7p-4)+15

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Solution for 7(2p+1)=2(7p-4)+15 equation: 



7(2p+1)=2(7p-4)+15

We move all terms to the left:

7(2p+1)-(2(7p-4)+15)=0

We multiply parentheses

14p-(2(7p-4)+15)+7=0



We calculate terms in parentheses: -(2(7p-4)+15), so:

2(7p-4)+15

We multiply parentheses

14p-8+15

We add all the numbers together, and all the variables

14p+7

Back to the equation:

-(14p+7)



We get rid of parentheses

14p-14p-7+7=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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