7(2n+5)=7(7n+4)+5

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Solution for 7(2n+5)=7(7n+4)+5 equation: 



7(2n+5)=7(7n+4)+5

We move all terms to the left:

7(2n+5)-(7(7n+4)+5)=0

We multiply parentheses

14n-(7(7n+4)+5)+35=0



We calculate terms in parentheses: -(7(7n+4)+5), so:

7(7n+4)+5

We multiply parentheses

49n+28+5

We add all the numbers together, and all the variables

49n+33

Back to the equation:

-(49n+33)



We get rid of parentheses

14n-49n-33+35=0

We add all the numbers together, and all the variables

-35n+2=0

We move all terms containing n to the left, all other terms to the right

-35n=-2

n=-2/-35

n=2/35

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