7(2n+2)=7(9n+3)+7

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Solution for 7(2n+2)=7(9n+3)+7 equation: 



7(2n+2)=7(9n+3)+7

We move all terms to the left:

7(2n+2)-(7(9n+3)+7)=0

We multiply parentheses

14n-(7(9n+3)+7)+14=0



We calculate terms in parentheses: -(7(9n+3)+7), so:

7(9n+3)+7

We multiply parentheses

63n+21+7

We add all the numbers together, and all the variables

63n+28

Back to the equation:

-(63n+28)



We get rid of parentheses

14n-63n-28+14=0

We add all the numbers together, and all the variables

-49n-14=0

We move all terms containing n to the left, all other terms to the right

-49n=14

n=14/-49

n=-2/7

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