7(2n+1)=7(6n+2)+1

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Solution for 7(2n+1)=7(6n+2)+1 equation: 



7(2n+1)=7(6n+2)+1

We move all terms to the left:

7(2n+1)-(7(6n+2)+1)=0

We multiply parentheses

14n-(7(6n+2)+1)+7=0



We calculate terms in parentheses: -(7(6n+2)+1), so:

7(6n+2)+1

We multiply parentheses

42n+14+1

We add all the numbers together, and all the variables

42n+15

Back to the equation:

-(42n+15)



We get rid of parentheses

14n-42n-15+7=0

We add all the numbers together, and all the variables

-28n-8=0

We move all terms containing n to the left, all other terms to the right

-28n=8

n=8/-28

n=-2/7

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