7(2j-8)=3(11j-6)

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Solution for 7(2j-8)=3(11j-6) equation: 



7(2j-8)=3(11j-6)

We move all terms to the left:

7(2j-8)-(3(11j-6))=0

We multiply parentheses

14j-(3(11j-6))-56=0



We calculate terms in parentheses: -(3(11j-6)), so:

3(11j-6)

We multiply parentheses

33j-18

Back to the equation:

-(33j-18)



We get rid of parentheses

14j-33j+18-56=0

We add all the numbers together, and all the variables

-19j-38=0

We move all terms containing j to the left, all other terms to the right

-19j=38

j=38/-19

j=-2

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