7(2b-6)=-10-2b

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Solution for 7(2b-6)=-10-2b equation: 



7(2b-6)=-10-2b

We move all terms to the left:

7(2b-6)-(-10-2b)=0

We add all the numbers together, and all the variables

7(2b-6)-(-2b-10)=0

We multiply parentheses

14b-(-2b-10)-42=0

We get rid of parentheses

14b+2b+10-42=0

We add all the numbers together, and all the variables

16b-32=0

We move all terms containing b to the left, all other terms to the right

16b=32

b=32/16

b=2

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