7(2b-4)=5(2-2b+6)

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Solution for 7(2b-4)=5(2-2b+6) equation: 



7(2b-4)=5(2-2b+6)

We move all terms to the left:

7(2b-4)-(5(2-2b+6))=0

We add all the numbers together, and all the variables

7(2b-4)-(5(-2b+8))=0

We multiply parentheses

14b-(5(-2b+8))-28=0



We calculate terms in parentheses: -(5(-2b+8)), so:

5(-2b+8)

We multiply parentheses

-10b+40

Back to the equation:

-(-10b+40)



We get rid of parentheses

14b+10b-40-28=0

We add all the numbers together, and all the variables

24b-68=0

We move all terms containing b to the left, all other terms to the right

24b=68

b=68/24

b=2+5/6

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