7(2b-2)=2(1-b)

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Solution for 7(2b-2)=2(1-b) equation: 



7(2b-2)=2(1-b)

We move all terms to the left:

7(2b-2)-(2(1-b))=0

We add all the numbers together, and all the variables

7(2b-2)-(2(-1b+1))=0

We multiply parentheses

14b-(2(-1b+1))-14=0



We calculate terms in parentheses: -(2(-1b+1)), so:

2(-1b+1)

We multiply parentheses

-2b+2

Back to the equation:

-(-2b+2)



We get rid of parentheses

14b+2b-2-14=0

We add all the numbers together, and all the variables

16b-16=0

We move all terms containing b to the left, all other terms to the right

16b=16

b=16/16

b=1

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