7(2a+4)=6(5a-3)+10

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Solution for 7(2a+4)=6(5a-3)+10 equation: 



7(2a+4)=6(5a-3)+10

We move all terms to the left:

7(2a+4)-(6(5a-3)+10)=0

We multiply parentheses

14a-(6(5a-3)+10)+28=0



We calculate terms in parentheses: -(6(5a-3)+10), so:

6(5a-3)+10

We multiply parentheses

30a-18+10

We add all the numbers together, and all the variables

30a-8

Back to the equation:

-(30a-8)



We get rid of parentheses

14a-30a+8+28=0

We add all the numbers together, and all the variables

-16a+36=0

We move all terms containing a to the left, all other terms to the right

-16a=-36

a=-36/-16

a=2+1/4

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