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7(2+x)=6(1+x)
We move all terms to the left:
7(2+x)-(6(1+x))=0
We add all the numbers together, and all the variables
7(x+2)-(6(x+1))=0
We multiply parentheses
7x-(6(x+1))+14=0
We calculate terms in parentheses: -(6(x+1)), so:We get rid of parentheses
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
7x-6x-6+14=0
We add all the numbers together, and all the variables
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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