7(2+x)=5(x-1,2)+35

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Solution for 7(2+x)=5(x-1,2)+35 equation:



7(2+x)=5(x-1.2)+35
We move all terms to the left:
7(2+x)-(5(x-1.2)+35)=0
We add all the numbers together, and all the variables
7(x+2)-(5(x-1.2)+35)=0
We multiply parentheses
7x-(5(x-1.2)+35)+14=0
We calculate terms in parentheses: -(5(x-1.2)+35), so:
5(x-1.2)+35
We multiply parentheses
5x-6+35
We add all the numbers together, and all the variables
5x+29
Back to the equation:
-(5x+29)
We get rid of parentheses
7x-5x-29+14=0
We add all the numbers together, and all the variables
2x-15=0
We move all terms containing x to the left, all other terms to the right
2x=15
x=15/2
x=7+1/2

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