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7(2+5v)=35v+14
We move all terms to the left:
7(2+5v)-(35v+14)=0
We add all the numbers together, and all the variables
7(5v+2)-(35v+14)=0
We multiply parentheses
35v-(35v+14)+14=0
We get rid of parentheses
35v-35v-14+14=0
We add all the numbers together, and all the variables
=0
v=0/1
v=0
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