7(2+3x)=4(2x-4)

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Solution for 7(2+3x)=4(2x-4) equation: 



7(2+3x)=4(2x-4)

We move all terms to the left:

7(2+3x)-(4(2x-4))=0

We add all the numbers together, and all the variables

7(3x+2)-(4(2x-4))=0

We multiply parentheses

21x-(4(2x-4))+14=0



We calculate terms in parentheses: -(4(2x-4)), so:

4(2x-4)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

21x-8x+16+14=0

We add all the numbers together, and all the variables

13x+30=0

We move all terms containing x to the left, all other terms to the right

13x=-30

x=-30/13

x=-2+4/13

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