7(1b+5)=(3b/10)

Solution for 7(1b+5)=(3b/10) equation:

7(1b+5)=(3b/10)

We move all terms to the left:

7(1b+5)-((3b/10))=0

We add all the numbers together, and all the variables

7(b+5)-((+3b/10))=0

We multiply parentheses

7b-((+3b/10))+35=0

We multiply all the terms by the denominator


7b*10))-((+3b+35*10))=0

We add all the numbers together, and all the variables

7b*10))-((3b+350))=0

We add all the numbers together, and all the variables

7b*10))-((3b=0

Wy multiply elements

70b^2=0

a = 70; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·70·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{140}=0$