7(11+x)=3(2x+35)

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Solution for 7(11+x)=3(2x+35) equation: 



7(11+x)=3(2x+35)

We move all terms to the left:

7(11+x)-(3(2x+35))=0

We add all the numbers together, and all the variables

7(x+11)-(3(2x+35))=0

We multiply parentheses

7x-(3(2x+35))+77=0



We calculate terms in parentheses: -(3(2x+35)), so:

3(2x+35)

We multiply parentheses

6x+105

Back to the equation:

-(6x+105)



We get rid of parentheses

7x-6x-105+77=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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