7(10(3x+x)+x)=4(10x+3+x)

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Solution for 7(10(3x+x)+x)=4(10x+3+x) equation: 



7(10(3x+x)+x)=4(10x+3+x)

We move all terms to the left:

7(10(3x+x)+x)-(4(10x+3+x))=0

We add all the numbers together, and all the variables

7(10(+4x)+x)-(4(11x+3))=0



We calculate terms in parentheses: -(4(11x+3)), so:

4(11x+3)

We multiply parentheses

44x+12

Back to the equation:

-(44x+12)



We get rid of parentheses

7(10(+4x)+x)-44x-12=0

We add all the numbers together, and all the variables

-44x+7(10(+4x)+x)-12=0

We move all terms containing x to the left, all other terms to the right

-44x+7(10(+4x)+x)=12

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