7(1-y)=3y-2)

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Solution for 7(1-y)=3y-2) equation: 



7(1-y)=3y-2)

We move all terms to the left:

7(1-y)-(3y-2))=0

We add all the numbers together, and all the variables

7(-1y+1)-(3y-2))=0

We multiply parentheses

-7y-(3y-2))+7=0

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