7(1-y)=13(y-2)

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Solution for 7(1-y)=13(y-2) equation: 



7(1-y)=13(y-2)

We move all terms to the left:

7(1-y)-(13(y-2))=0

We add all the numbers together, and all the variables

7(-1y+1)-(13(y-2))=0

We multiply parentheses

-7y-(13(y-2))+7=0



We calculate terms in parentheses: -(13(y-2)), so:

13(y-2)

We multiply parentheses

13y-26

Back to the equation:

-(13y-26)



We get rid of parentheses

-7y-13y+26+7=0

We add all the numbers together, and all the variables

-20y+33=0

We move all terms containing y to the left, all other terms to the right

-20y=-33

y=-33/-20

y=1+13/20

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