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7(1-x)=3(x+4)
We move all terms to the left:
7(1-x)-(3(x+4))=0
We add all the numbers together, and all the variables
7(-1x+1)-(3(x+4))=0
We multiply parentheses
-7x-(3(x+4))+7=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
-7x-3x-12+7=0
We add all the numbers together, and all the variables
-10x-5=0
We move all terms containing x to the left, all other terms to the right
-10x=5
x=5/-10
x=-1/2
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