7(1-3y)+9=13(2y+4)

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Solution for 7(1-3y)+9=13(2y+4) equation: 



7(1-3y)+9=13(2y+4)

We move all terms to the left:

7(1-3y)+9-(13(2y+4))=0

We add all the numbers together, and all the variables

7(-3y+1)-(13(2y+4))+9=0

We multiply parentheses

-21y-(13(2y+4))+7+9=0



We calculate terms in parentheses: -(13(2y+4)), so:

13(2y+4)

We multiply parentheses

26y+52

Back to the equation:

-(26y+52)



We add all the numbers together, and all the variables

-21y-(26y+52)+16=0

We get rid of parentheses

-21y-26y-52+16=0

We add all the numbers together, and all the variables

-47y-36=0

We move all terms containing y to the left, all other terms to the right

-47y=36

y=36/-47

y=-36/47

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